Question

p.t tan theata +sec thrata-1÷tan theata-sec theata-1=sec theata tan theata​

Answer 1

Answer:

Step-by-step explanation:

=tan+sec-1/tan-sec-1

=tan+sec-(sec^2-tan^2)/tan-sec-1

=tan+sec-(tan+sec)(tan-sec)/tan-sec-1

=tan+sec(tan-sec-1)/tan-sec-1

=tan+sec