Question

P.T TanA=sin2a/1+cos2a​

Answer 1

Step-by-step explanation:

We have,

Let A=α So,

$\tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) }$

$= > \tan( \alpha ) = \frac{ \sin( \alpha ) \cos( \alpha ) }{ \cos^{2} ( \alpha ) }$

$= > \tan( \alpha ) = \frac{2 \sin( \alpha ) \cos( \alpha ) }{2 \cos^{2} ( \alpha ) }$

$= > \tan( \alpha ) = \frac{ \sin(2 \alpha ) }{1 + \cos( 2\alpha ) }$