Math, asked by pvbnageshkumar, 11 months ago

P.T TanA=sin2a/1+cos2a​

Answers

Answered by senboni123456
1

Step-by-step explanation:

We have,

Let A=α So,

 \tan( \alpha )  =  \frac{ \sin( \alpha ) }{ \cos( \alpha ) }

 =  >  \tan( \alpha )  =  \frac{ \sin( \alpha )  \cos( \alpha ) }{ \cos^{2} ( \alpha ) }

 =  >  \tan( \alpha )  =  \frac{2 \sin( \alpha ) \cos( \alpha )  }{2 \cos^{2} ( \alpha ) }

 =  >  \tan( \alpha )  =  \frac{ \sin(2 \alpha ) }{1 +  \cos( 2\alpha ) }

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