Question

P.T
tano + coto = Seco. Coseco​

Answer 1

Answer:

$\tan( \alpha ) + \cot( \alpha ) \\ \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \alpha ) } \\ \\ by \: taking \: lcm \: \\ \\ \frac{ { \sin}^{2} \alpha + { \cos }^{2} \alpha }{ \sin( \alpha) \times \cos( \alpha ) } \\ \\ \frac{1}{ \sin( \alpha ) \times \cos( \alpha ) } \\ \\ \sec( \alpha ) \times \csc( \alpha )$