Math, asked by daranasha, 1 year ago

p
 {x}^{2}  - 15 \div 9 + 4 \div 9 = 0

Answers

Answered by Anonymous
1
Heya buddy !

x^2 -15/9 +4/9 =0

=> x^2 -(15+4)/9 =0

=> x^2 -19/9 =0

=> x^2 = 19/9

x = under root 19/9
Answered by mysticd
0
Hi ,

x² - 15/9 + 4/9 = 0

x² - ( 15 - 4 ) /9 = 0

x² - 11/9 = 0

x² = 11/9

x = ± √11/9

x = ± ( √11 ) / 3

I hope this helps you.

: )
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