Question

P to the power 6 - 4p to the power 3 +4 factorise the above

Answer 1

$\boxed{\boxed{\boxed{\bold{\green{solution :\longrightarrow}}}}}$

$\bold{\underline{ {p}^{6} - 4 {p}^{3} + 4}} \\ \\ \bold{= {(p}^{3} ) {}^{2} - 2. {p}^{3} .2 + {(2)}^{2}} \\ \\ \bold{= ( {p}^{3} - 2) {}^{2}} \\ \\ \bold{= ( {p}^{3} - 2)( {p}^{3} - 2)}$