Question

P-V diagram of a cyclic process ABCA is shown in the figure. The temperature of gas will be maximum at?

Answer 1

Answer:

P

Explanation:

because it is at great height than others

Answer 2

Answer:

The temperature of the gas will be maximum at points A and B.

Ideal Gas Law:

• The ideal gas law is an equation of a hypothetically perfect gas.
• It combines Boyle's law, Charles's law, Avogadro's law, and Gay-Lussac's law.
• It is given as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
• This law holds for all gases.

Explanation:

At point C, pressure is $P_{0}$ and volume is $V_{0}$. Substituting these values in the ideal gas equation, we get

$P_{0}V_{0} = nRT$

$T=\frac{P_{0}V_{0} }{nR}$ ... (i)

At point A, pressure is $2P_{0}$ and volume is $2V_{0}$. Substituting these values in the ideal gas equation, we get

$2P_{0}2V_{0} = nRT$

$4P_{0}V_{0} = nRT$

$T=4\frac{P_{0}V_{0} }{nR}$ ...(ii)

At point B, pressure is $P_{0}$ and volume is $4V_{0}$. Substituting these values in the ideal gas equation, we get

$P_{0}4V_{0} = nRT$

$4P_{0}V_{0} = nRT$

$T=4\frac{P_{0}V_{0} }{nR}$  ...(iii)

From equations (i), (ii), and (iii), it is clear that the temperature is higher at points A and B.

Therefore, in the given cyclic process, the gas will have a maximum temperature at point A and point B.

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