Question

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Answer 1

Answer:

15).

The coordinates of a point which divided two points (x1,y1) and (x2,y2)

internally in the ratio m:n is given by the formula,

(x,y)=(mx2+nx1m+n,my2+ny1m+n)

The points of trisection of a line are the points which divide the line into the ratio 1: 2.

Here we are asked to find the points of trisection of the line segment joining the points A(5,−6) and B(−7,5).

So we need to find the points which divide the line joining these two points in the ratio 1: 2 and 2: 1.

Let P(x, y) be the point which divides the line joining ‘AB’ in the ratio 1 : 2.

(x,y)=((1-(-7)+2(5)1+2),(1(5)+2(-6)1+2))

(x,y)=(1,73)

Let Q(e, d) be the point which divides the line joining ‘AB’ in the ratio 2 : 1.

(e, d) =

((1(5)+2(-7)1+2), (1(-6)+ 2(5)1+2)

(e,d)=(-3,43)

Therefore the points of trisection of the line joining the given points are

(1,73)and(-3,43)

Step-by-step explanation:

hope it helps ✌️✌️