p varies directly as square of q and p is equal to 4 when q=2/3 . find p when q=8/3
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Answered by
45
Step-by-step explanation:
given: p varies directly as square of q (i.e) p ~ q^2
that is p=k q^2 , where k is a constant
when q=2/3 p=4
4=k(2/3)^2
4=k(4/9) ====> 4k/9= 4
4k=36 ====> k=9
when q=8/3
p= 9 (8/3)^2
p= 9×64/9
p= 64
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12
Hi learner you can easily solve this question when you know the base of this chapter so start learning from the beginning and try to solve examples of books by yourself
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