Math, asked by NishchalTiwari, 4 months ago

p varies directly as square of q and p is equal to 4 when q=2/3 . find p when q=8/3​

Answers

Answered by sudhar1310
45

Step-by-step explanation:

given: p varies directly as square of q (i.e) p ~ q^2

that is p=k q^2 , where k is a constant

when q=2/3 p=4

4=k(2/3)^2

4=k(4/9) ====> 4k/9= 4

4k=36 ====> k=9

when q=8/3

p= 9 (8/3)^2

p= 9×64/9

p= 64

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Answered by Rehansir
12

Hi learner you can easily solve this question when you know the base of this chapter so start learning from the beginning and try to solve examples of books by yourself

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