Question

p varies directly as the square root of q . When p = 40, q = 16, if p is 10 than find q = ? ​

Answer 1

Step-by-step explanation:

$p = k\sqrt{q }$

$40 = k \sqrt{16}$

$40 = 4k \\ k = 10$

when p= 10

$10 = 10 \sqrt{q} \\ \sqrt{q} = 1 \\ q = 1$