Question

p varies inversely as (q + 5). If p = 6 when q =

1, find p when q = - 1.

(a) 9 (b) 12

(c) – 6 (d) – 3

a is the ans how plzz explain​

Answer 1

Answer:

given

p. cx. 1/(q+5)

p = k/(p+5) where k is constant of proportion

given when p = 6, q = 1

6 = k/(1+5)

6 = k/6

k = 6*6

k = 36

hence

p = 36/(q+5)

when q= -1

p = 36/(-1+5)

= 36/4

p = 9