Question

P(X) = 0.15, P(Y) = 0.25, P(X∩Y) = 0.10 then P(XUY) is
(a) 0.10
(b) 0.20
(c) 0.30
(d) 0.40

Answer 1

the answer is c.Because the formula is P(XUY)=P(X)+P(Y)-P(XnY)

Answer 2

Hi ,

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By addition theorem on

probability:

If X and Y are any two events in a

sample space S , then

P( X U B ) = P(X)+P(Y)- P( X and Y )

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It is given that ,

P( X ) = 0.15

P( Y ) = 0.25

P( X and Y ) = 0.10

P( X U Y ) = ?

P( X U B ) = 0.15 + 0.25 - 0.10

= 0.40 - 0.10

= 0.30

Therefore ,

Option ( c ) is correct.

I hope this helps you.

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