Math, asked by sumaiyatabassumahona, 5 hours ago

P × x ^ 2 + 16y ^ 2 = 400 crosses the ellipse (2√2, 5 √ √2). (A) Determine the value of P. (B) Find the eccentricity of the ellipse, the coordinates of the two epicenters, the length of the epicenter perpendicular and the equation 4 of the control line. (C) Find the equation of an ellipse whose large axis and small axis are equal to the lengths of x and y-axis, epicenter (+ -2,0) and large axis equal to the length of the small axis of the stimulus ellipse.​

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Answered by princekumarvarma3
0

Answer:

False <br> Given equation of the ellipse is

<br> which is in form of

where

<br>

Foci,S=(0,be),S'(0,-be) <br>

<br>

<br> Foci, S=

<br> Let the coordinates of points P be be (x,y) then PS+PS'=2b=

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