Question

p(x) =2+x+2x^2 - x^3 at x=0,x=1 and x=2​

Answer 1

When x=0

p[0]=2+0+2×0²

2+0+0

2

When x=1

p[1]=2+1+2×1²

2+1+2

5

When x=2

p[2]=2+2+2×2²

4+8

12

Answer 2

Step-by-step explanation:

GIVEN P(X)..

-x³+2x²+x+2

PUT x = 0 ...we get,

0+0+0+2=2

PUT x= 1....we get,

-1+2+1+2=4

PUT x= 2...we get ,

-8+8+2+2= 4

hope it helps...

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