Question

P(x)=2011(x+1)(x-2)(x+3)(x-5) find the zeros of polynomial ​

Answer 1

Answer:

$p(x) = 2011(x + 1)(x - 2)(x + 3)(x - 5) \\ p(0) = 2011(0 + 1)(0 - 2)(0 + 3)(0 - 5) \\ p(0) = 2011(1)( - 2)(3)( - 5) \\ p(0) = 2011(3)( - 2)( - 5) \\ p(0) = 6033(10) \\ p(0) = 60330$