Question

P(x)=2x^2+3x+1 find the zeros

Answer 1

thanku..............

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Answer 2

$2 {x}^{2} + 3x + 1 = 0 \\ 2 {x}^{2} + x + 2x + 1 = 0 \\ x(2x + 1) + 1(2x + 1) = 0 \\ (x + 1)(2x + 1) = 0 \\ x = - 1 \\ x = - 1 \div 2$

$\boxed{x=-1,x=-1/2}$

Hope it helps