Question

P(X)=2X^2-KX+7 and Q(X)=5X^2+2X-K if P(2)=Q(3). The value of K=

Answer 1

Question

P(X)=2x² - kx + 7 and Q(X)= 5x²+2x-k if P(2)=Q(3). The value of K= ?

Solution

Given :-

• P(x) = 2x² - kx + 7
• Q(x) = 5x²+2x-k

And,

• P(2) = Q(3)

Find :-

• Value of k

Explanation

For This, Keep value of x = 2 in P(x)

==> P(2) = 2 * 2² - k*2 + 7

==>P(2) = 2 * 4 - 2k + 7

==> P(2) = 8 + 7 - 2k

==> P(2) = 15 - 2k

Again, Keep value of x = 3 in Q(x)

==> Q(3) = 5 * 3² + 2 * 3 - k

==> Q(3) = 5 *9 + 6 - k.

==> Q(3) = 45 + 6 - k

==> Q(3) = 51 - k

So, Here

• P(2) = Q(3)

Then,

==> 15 - 2k = 51 - k

==> 2k - k = 15 - 51

==> k = -36

Hence

• Value of k = -36

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