Question

P(x) = 2x^3-9x² + x +15, g(x) = 2x - 3.
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Answer 1

$\mathcal{\underline{\underline{SOLUTION:-}}}$

Given that g(x)=2x-3

2x-3=0

2x=3

$\boxed{x=3/2}$

Now let's substitute the value of x in P(x)

$=2x^3-9x^2+x+15$

$=2×(3/2)^3-9(3/2)^2+ 3/2+15$

$=3×3/2×3/2-81/4+3/2+15$

$=27/4-81/4+3/2+15$

$=3$

$textbf{\underline{\underline{MUST\:TO\:REMEMBER}}}$

OBSERVE THE POSITIVE AND NEGATIVE SIGNS WHILE SOLVING THESE TYPE OF PROBLEMS.MULTIPLY THE FRACTIONS CORRECTLY.FIND THE "X" VALUE IN THE BEGINNING BEFORE SOLVING THE TOTAL SUM

Answer 2

Answer:

Given that g(x)=2x-3

2x-3=0

2x=3

\boxed{x=3/2}

x=3/2

Now let's substitute the value of x in P(x)

=2x^3-9x^2+x+15=2x

3

−9x

2

+x+15

=2×(3/2)^3-9(3/2)^2+ 3/2+15=2×(3/2)

3

−9(3/2)

2

+3/2+15

=3×3/2×3/2-81/4+3/2+15=3×3/2×3/2−81/4+3/2+15

=27/4-81/4+3/2+15=27/4−81/4+3/2+15

=3=3