p(x)=2x^3-x^2-13x+6 factorise
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wait first of all it is -6
for this you have to use hit and trial method. until we get whole equation equal to zero
let's take x=-2
p(x)= -16-4+26-6=0
so x=-2
then x+2
now divide p(x)=2x^3-x^2-13x+6 by x+2
by dividing u will get
p(x)=(x+2)(2x^2 -5x-3)
=(x+2)(2x^2-6x+x-3)
=(x+2)(2x+1)(x-3)
PS: question was nice☺️
for this you have to use hit and trial method. until we get whole equation equal to zero
let's take x=-2
p(x)= -16-4+26-6=0
so x=-2
then x+2
now divide p(x)=2x^3-x^2-13x+6 by x+2
by dividing u will get
p(x)=(x+2)(2x^2 -5x-3)
=(x+2)(2x^2-6x+x-3)
=(x+2)(2x+1)(x-3)
PS: question was nice☺️
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