P(x)=2x²+3x-5 find P(1),P(2),P(0) i.e substitute x=1,x=2 & x=0 and simplify P(2)+P(1)-P(0)
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Answer:
p(x)=2x^2+3x-5
p(0)=2(0)^2+3(0)-5
=-5
p(1)=2(1)^2+3(1)-5
=2+3-5
=0
p(2)=2(2)^2+3(2)-5
=8+6-5
=9
p(3)=2(3)^2+3(3)-5
=18+9-5
=22
simplify:-p(2)+p(1)-p(0)
=9+0-(-5)
=9+5
=14
Hope this helps you........ ❤❤
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