Question

ਜੇਕਰ p(x) = 2x2 + 4x + 6 ਇੱਕ ਦੋ ਘਾਤੀ ਬਹੁਪਦ ਹੈ ਤਾਂ p(x) ਦੇ ਸਿਫਰਾਂ ਦਾ ਜੋੜਫਲ ਕੀ ਹੈ?​

Answer 1

If p (x) = 2x2 + 4x + 6 is a two exponential polynomial then what is the sum of the zeros of p (x)?

$\textbf{Given:}$

$\textsf{Polynomial is}\;\mathsf{P(x)=2x^2+4x+6}$

$\textbf{To find:}$

$\textsf{Sum of zeroes of P(x)}$

$\textbf{Solution:}$

$\textbf{Concept used:}$

$\boxed{\begin{minipage}{6cm} \\\mathsf{If\;\alpha\;and\;\beta\;are\;zeroes\;of\;ax^2+bx+c}\\\\\mathsf{then,\;Sum\;of\;zeroes=\dfrac{-b}{a}}\\ \end{minipage}}$

$\mathsf{Consider,}$

$\mathsf{P(x)=2x^2+4x+6}$

$\mathsf{sum\;of\;zeroes=\dfrac{-b}{a}}$

$\mathsf{sum\;of\;zeroes=\dfrac{-4}{2}}$

$\implies\boxed{\mathsf{sum\;of\;zeroes=-2}}$

$\textbf{Find more:}}$

Obtain other zeroes of the polynomial

f(x) = 2x4 + 3x3 - 5x2 - 9x - 3

if two of its zeroes are √3 and - √3.​

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If a and b are the zeros of polynomial 6x²-(k+1)-7x such that one zero is 11/6 more than the other, find the value of k.

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Answer 2

Step-by-step explanation:

Given  If p (x) = 2x2 + 4x + 6 is a two exponential polynomial then what is the sum of the zeros of p(x)?

• Given equation is  p(x) = 2x^2 + 4x + 6
• So we have the quadratic polynomial as ax^2 + bx + c = 0
• So the sum of zeroes = - b/a
• Comparing with the given equation we have a = 2, b = 4 and c = 6
• So we get sum of zeroes = - 4/2
•                                        = - 2
• Therefore the sum of zeroes of p(x) = - 2

Reference link will be

https://brainly.in/question/31024345