Question

p(x)= 2x3 -x 2 -px-2 i) find p is (x-2) is a factor of p(x)​

Answer 1

Answer:

first find zero of polynomial of divisor x-2

x-2=0

x=2

substitute x=2 value in p(x)

p(2)=2(2)^3-(2)^2-p(2)-2=0

=16-4-2-2p=0

=10-2p=0

transport 2p to right

10=2p

p=5