p(x)=2x3+x2-2x+1,g(x)=x+1
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Apply remainder theorem
=>x + 1 =0
=> x = - 1
Replace x by – 1 we get
=>2x3 + x2 – 2x – 1
=>2(-1)3 + (-1)2 -2(-1) - 1
=> -2 + 1 + 2 - 1
=> 0
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