p(x)=2x4+7x3-8x2-14x+8 g(x)=x2+0x-2
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Given, – √2 and √2 are zeros of p(x).
⇒ (x + √2) and (x – √2) are the factors of p(x).
Thus (x + √2) (x – √2) = (x2 – 2) is also a factor of p(x).
To find the remaining zeros, we find the remaining factors using the division process.
Here, dividend polynomial = p(x) = 2x4 + 7x3 — 8x2 — 14x + 8
and divisor polynomial = s(x) = x2 – 2
I have do half only
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