Question

P(x) = 2x4-ax3 +4x2+2x+1, find value of a
p(1/2)
​

Answer 1

ANSWER:-

$p(\frac{1}{2})=\frac{189a}{128}$

QUESTION:-

$p(x)=2x^4-ax^3+4x^2+2x+2$

TO FIND:-

$P(\frac{1}{2} )$

EXPLANATION:-

LET'S SUBSTITUTE X BY 1/2 ,SO WE GET

$p(\frac{1}{2}) =2(\frac{1}{4} )^4+a(\frac{1}{4})^3+4(\frac{1}{4})^2+2(\frac{1}{2})+1\\\\\\p(\frac{1}{2})=\frac{1}{128}+\frac{a}{64}+\frac{1}{4}+2\\\\\\p(\frac{1}{2})=\frac{1+2a+32+156}{128} \\\\\\p(\frac{1}{2})=\frac{189a}{128}$