Question

p(x) =2x⁴+x³-8²-x+6;g(x)=2x-3​

Answer 1

Step-by-step explanation:

Heya user this is your answer...

2x-3 can be written as 2x-3=0

2x=3.

x=3/2

Now by substituting x value we get,

2x3/2x3/2x3/2x3/2+3/2x3/2x3/2-8x3/2x3/2-3/2+6

By cancelling numerator and denominator we get,

81/8+27/8-18-3/2+6

108/8-18-3/2+6

now by taking LCM..

108/8-144/8-12/8+48/8

-36/8-12/8+48/8

-48/8+48/8

0/8=0

Hope it helps

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