p={x:3(3x+2)>7x-2;x belongs to R}. q={x:4(4x-15)>=3(4x-3);x belongs to I} . find the range of p-q ,p intersection q
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Answer:
Here is ur answer dear....❤❤❤
P(x) = x^3 - 4x^2 + x + 6
=> p (3) = ( 3)^3 - 4(3)^2 + (3) + 6
=> p(3) = 27 - 36 + 3 + 6
=> p(3) = 27 - 36 + 9
=> p(3) = 27 + 9 - 36
=> p(3) = 36 - 36
=> p(3) = 0
Now,
x^3 - 4x^2 + x + 6
= x^3 - 2x^2 - 2x^2 + 4x - 3x + 6
= x^2 ( x - 2) - 2x ( x - 2) - 3(x - 2)
= ( x - 2) (x^2 - 2x - 3)
= (x-2) [ x^2 - 3x + x - 3]
= (x - 2) [ x (x - 3) + 1 (x - 3)]
= (x-2)(x-3) (x+1)
hope it helps u.......follow me.......
plz mark it as a brainliest answer. ......❤❤❤❤❤
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0
Answer:
hey mate here is ur answer
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