Question

p (x)=3x+1,x=-1/3 verify zeroes of polynomial show method also​

Answer 1

$x=\dfrac{-1}{3}$ is a zero of $p(x)=3x+1$

Step-by-step explanation:

Since we have given that

$p(x)=3x+1$

and $x=\dfrac{-1}{3}$

We need to check the zeroes of polynomial.

First we put the value of x in the given polynomial to check whether it gives 0 or not.

So, it becomes,

$p(\dfrac{-1}{3})=3(\dfrac{-1}{3})+1=-1+1=0$

Hence, $x=\dfrac{-1}{3}$ is a zero of $p(x)=3x+1$

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P (x)=3x+1,x=-1/3 verify zeroes of polynomial show method also​

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Answer 2

Step-by-step explanation:

3x+1

Since we have given that

p(x)=3x+1p(x)=3x+1

and x=\dfrac{-1}{3}x=3−1

We need to check the zeroes of polynomial.

We need to check the zeroes of polynomial.First we put the value of x in the given polynomial to check whether it gives 0 or not.

We need to check the zeroes of polynomial.First we put the value of x in the given polynomial to check whether it gives 0 or not.So, it becomes,

We need to check the zeroes of polynomial.First we put the value of x in the given polynomial to check whether it gives 0 or not.So, it becomes,p(\dfrac{-1}{3})=3(\dfrac{-1}{3})+1=-1+1=0p(3−1)=3(3−1)+1=−1+1=0

We need to check the zeroes of polynomial.First we put the value of x in the given polynomial to check whether it gives 0 or not.So, it becomes,p(\dfrac{-1}{3})=3(\dfrac{-1}{3})+1=-1+1=0p(3−1)=3(3−1)+1=−1+1=0Hence, x=\dfrac{-1}{3}x=3−1 is a zero of p(x)=3x+1p(x)=3x+1