Math, asked by madihakhan2546, 6 months ago

p(x)=3x+1,x=-1upon3​

Answers

Answered by Mora22
0

<marquee>Your \:  answer

 \rm{p(x) = 3x + 1}

 \sf{if \:x =  \frac{ - 1}{3} }

 \mathfrak{p(x) = 0}

 \mathcal{i.e \: x =  \frac{ - 1}{3}is \: a \: root }

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