Math, asked by haselak818, 7 months ago

p (x) = 3x^2 -1

x = -1/√3​

Answers

Answered by Anonymous
1

p(x) =  {3x}^{2}  - 1

 x =  \frac{ - 1}{ \sqrt{3} }

 = 3 { \binom{ - 1}{ \sqrt{3} } }^{2}  - 1

1 - 1 = 0

hope it helps u....!!!

Answered by harsh253714
0

p(x) =  {3x}^{2}  - 1

x =  \frac{ - 1}{ \sqrt{3} }

 = 3 { \binom{ - 1}{ \sqrt{3} } }^{2}  - 1

1 - 1 = 0

hope it helps u....!!!

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