Question

p(x)=3x^2-1,x=-1/√ 3

Answer 1

$3 {x}^{2} - 1 = 0 \\ 3 {x}^{2} = 1 \\ {x}^{2} = \frac{1}{3} \\ x = + - \sqrt{ \frac{1}{3} } \\ x = \frac{1}{ \sqrt{3} } \\ x = - \frac{1}{ \sqrt{3} }$
on putting any of x in it p(x)=0