Question

P(x) = 3x^2 +6x-12 where x = -3,-2,-1,0,1,2,3​

Answer 1

P(×)= 3x^2 + 6x - 12

P(-3)= 3(-3)^2 +6(-3) - 12

= 27 -18 -12

= -3

P(-2) = 3(-2)^2 + 6(-2) - 12

= 12 -12 -12

= - 12

P(-1) = 3(-1)^2 + 6(-1) - 12

= 3 - 6- 12

= - 15

P(0) = 3(0)^2 + 6 (0) - 12

= - 12

P(1) = 3(1)^2 + 6(1) - 12

= 3 + 6 - 12

= - 3

P(2)= 3(2)^2+ 6(2) -12

= 12

P(3) = 3(3)^2 +6(3)‐ 12

= 27 + 18- 12

= 30