Question

p(X)= 3x^3-2x^2+4x-5 find remainder of p(X) is divided by 3x-1​

Answer 1

Answer:

how do if FL oh cl it dj

Step-by-step explanation:

hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm hmm

go ph dh k

Answer 2

Answer:

-34/9

Step-by-step explanation:

Given p(x) = 3x^3-2x^2+4x-5

therefore zero of 3x-1 = 1/3

Now using remainder theorem :

p(x) = 3×(1/3)^3- 2×(1/3)^2 + 4(1/3) -5

= 1/9 -2/9 + 4/3 - 5

= 1-2 +12 -45/9

= -34/9