p(x)=3x^3-7x^2+1,p(0)=
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Answer:
p(0) = 1
Solution:
p(x) = 3x^3 - 7x^2 + 1
p(0) = 3(0)^3 - 7(0)^2 + 1
p(0) = 1
Hope this will be helpful to you
p(0) = 1
Solution:
p(x) = 3x^3 - 7x^2 + 1
p(0) = 3(0)^3 - 7(0)^2 + 1
p(0) = 1
Hope this will be helpful to you
Answered by
0
Answer:
I hope you understand and helpful please make me as Brainly
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