Math, asked by sivashankaryaddanapu, 6 months ago

p(x)=3x^3-7x^2+1,p(0)=​

Answers

Answered by dandi19
0
Answer:

p(0) = 1

Solution:

p(x) = 3x^3 - 7x^2 + 1

p(0) = 3(0)^3 - 7(0)^2 + 1

p(0) = 1


Hope this will be helpful to you
Answered by vaishanil12355
0

Answer:

I hope you understand and helpful please make me as Brainly

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