Question

P (x)=3x^3-x^2-ax-45
P (3)=0

Answer 1

by substituting X we get
p(x)=- 45-3a

and this is equal to zero because x minus 3 is the factor of this polynomial
so- 45-3a =0
>therefore
-3a=45
a=45/-3
a=-15

Answer 2

Answer:

Step-by-step explanation: