P (x)=3x^3-x^2-ax-45
P (3)=0
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by substituting X we get
p(x)=- 45-3a
and this is equal to zero because x minus 3 is the factor of this polynomial
so- 45-3a =0
>therefore
-3a=45
a=45/-3
a=-15
p(x)=- 45-3a
and this is equal to zero because x minus 3 is the factor of this polynomial
so- 45-3a =0
>therefore
-3a=45
a=45/-3
a=-15
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