Math, asked by AgrawalKashish, 1 year ago

P(x)= 3x square-1, In which the value of x= -1/root3 & 2/root 3

Answers

Answered by ShuchiRecites
12
\textbf{ Hello Mate! }

p(x) = 3x² - 1

Where value of x = - 1 / √3 and 2 / √3

p(x) = 3( - 1 / √3 )² - 1
= 3 × 1 / 3 - 1
= 1 - 1
= 0

p(x) = 3( 2 / √3 )² - 1
= 3 × 4 / 3 - 1
= 4 - 1
= 3

Hence, we get that - 1 / √3 is value of x but
2 / √3 is not value of x

Hope it helps
Answered by meetbhatia79
0

Answer:

this very exact answer of this question thank to help me

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