P(x)=3x square-1 Pls send the answer!!
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what is the question then I'll answer
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Answer:
If you are asking about the zeros then we have the following solution,
3x²-1=(√3x)²- (1)²=(√3x-1)(√3x+1)
Now, the zeroes are as follows :
1).=>√3x-1=0
=>√3x=1
=>x=1/√3
2)x=-1/√3
then we have,
α=1/√3
β=-1/√3
hope it helps mark me as the brainliest ....
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