P(x)=3x²-1,x
=-1\√3,2\√3
Answers
Answered by
152
P(x) = 3 ( x^2 - 1/3)
= 3 (x - 1/sqrt(3)) (x + 1/sqrt(3))
Roots are + or - 1/sqrt(3).
Qn is to find:
P(- 1/sqrt(3)) = 0 as one factor becomes 0. It's the root.
P(2/sqrt(3)) = 3* (2^2/3) - 1
= 3.
= 3 (x - 1/sqrt(3)) (x + 1/sqrt(3))
Roots are + or - 1/sqrt(3).
Qn is to find:
P(- 1/sqrt(3)) = 0 as one factor becomes 0. It's the root.
P(2/sqrt(3)) = 3* (2^2/3) - 1
= 3.
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Answered by
298
P(x) = 3x² -1
where , x = -1/√3 and 2/√3
put x = -1/√3 in P(x)
P(-1/√3) = 3(-1/√3)² -1
= 3×1/3 - 1
= 0
it means x = -1/√3 is a root of P(x) .
again, put x = 2/√3
P(2/√3) = 3(2/√3)² -1
= 3× 4/3 -1
= 4 -1 = 3
where , x = -1/√3 and 2/√3
put x = -1/√3 in P(x)
P(-1/√3) = 3(-1/√3)² -1
= 3×1/3 - 1
= 0
it means x = -1/√3 is a root of P(x) .
again, put x = 2/√3
P(2/√3) = 3(2/√3)² -1
= 3× 4/3 -1
= 4 -1 = 3
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