p(x)=3x³+7x,q(x)=7+3x
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Apply remainder theorem
=>7 + 3x =0
=> 3x = - 7
=> x = - 7/3
Replace x by - 7/3 we get
=>3x3 + 7x
=>3(-7/3)3 + 7(-7/3)
=>3(-343/27) – 49/3
=> (-343/9) – 49/3
This value is not equal to 0
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