p(x)=3x³+7x,q(x)=7+3x
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Answer:
let,
q (x)= 7+3x=0
so, x= -7/3
now put the value of x in p (x)
so, 3×(-7/3)3 + 7×-7/3
-343/9+(-49/3)
=54.44.............
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