Question

p(x)=3x³+7x,q(x)=7+3x




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Answer 1

Answer:

Apply remainder theorem

=>7 + 3x =0

=> 3x = - 7

=> x = - 7/3

Replace x by - 7/3 we get

=>3x3 + 7x

=>3(-7/3)3 + 7(-7/3)

=>3(-343/27) – 49/3

=> (-343/9) – 49/3

This value is not equal to 0

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