Question

p(x)=3x⁴-2x³+2x²-1 by q(x)=(x+1)​

Answer 1

Step-by-step explanation:

p(x) = 3x^4 - 2x^³+2x^2 - 1 ; q(x) = ( x + 1 )

soln: x + 1 = 0

x = 0 - 1

x = -1

p(-1) = 3 × (-1) ^4 - 2× ( -1 ) ^ 3 + 2× (-1)^2 - 1

= 3× 1 - (-2 ) × 1 + 2× 1 - 1

= 3 + 2 + 2 - 1

= 7 - 1 = 6

Answer 2

Step-by-step explanation:

x+1=0

x=-1

p(x)=3(-1)⁴-2(-1)³+2(-1)²+0x-1

=3+2+2-1

=7-1

=6