Question

p(x)=4+x^3-2x^2 find the value at x=0 , x=1 , x=(-2)​

Answer 1

Answer:

4,3,-12

Step-by-step explanation:

P(X=0) :- 4 +0-0=4

P(X=1) :- 4+1+-2=3

P(X=-2) :- 4-8-8=-12