Question

P(x)=4x^2-1 find the zero

Answer 1

$p(x) = 0 \\ 4 {x}^{2} - 1 = 0 \\ 4 {x}^{2} = 1 \\ {x}^{2} = \frac{1}{4}$

So,

$x = ± \sqrt{ \frac{1}{4} }$

Therefore, the zeroes of the polynomial are

$x = \frac{1}{2} , - \frac{1}{2}$