Question

P(x)=4x^-kx+9 can be written as the product of two first degree polynomials
*Find the least value of k
*Using this value of k.find the solution of p(x)=0

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required soluion is x=-3/2}}}$

Step-by-step explanation:

P(x)=4x^-kx+9

Determinant k^2-4*4*9=0

k^2=144

so k=12 or k=-12  

so p(x)=4x^2+12x+9=0, using k=-12

=>(2x+3)^2=0

=>x=-3/2