Question

P(X) = 4x² + 4√3x + 3 = 0. Find Alpha and Beta.​

Answer 1

Answer:

= $4x^2 + 2\sqrt{3x} + 3 = 0$

= $2x (2x + \sqrt{3} ) +\sqrt{3} (2x + \sqrt{3} )$

= $(2x + \sqrt{3} ) = 0$      = $(2x + \sqrt{3} ) = 0$

= $2x = -\sqrt{3}$            = $2x = -\sqrt{3}$

= $x$ = -√3/2             = $x$ = -√3/2

∴ ∝ = -√3/2,  β = -√3/2