P(x) =5x2
+ 4y + z, p(1) =________
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idk-mwnb-pbe G..I..R..L..S.want to see my P..E..N..I..E..S..E
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If P(x)= 5x^2+4y+z
Then,
P(1)= 5(1^2)+2+4y+z
= 5+2+4y+z
= 6+4y+z
Hence, P(1)= 6+4y+z
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