Question

p(x)=5x³-7x²+8x+100. find p(0)and p(1)​

Answer 1

p(0) = 100 , p(1) = 106

Given :

p(x) = 5x³ - 7x² + 8x + 100

To find :

The value of p(0) & p(1)

Solution :

Step 1 of 2 :

Write down the given polynomial

Here the given polynomial is

p(x) = 5x³ - 7x² + 8x + 100 - - - - (1)

Step 2 of 2 :

Find the value of p(0) & p(1)

Putting x = 0 in (1) we get

$\displaystyle \sf p(0) = 5 \times {(0)}^{3} - 7 \times {0}^{2} + 8 \times 0 + 100$

$\displaystyle \sf{ \implies } p(0) = 0 - 0 + 0 + 100$

$\displaystyle \sf{ \implies }p(0) = 100$

Putting x = 1 in (1) we get

$\displaystyle \sf p(1) = 5 \times {(1)}^{3} - 7 \times {1}^{2} + 8 \times 1 + 100$

$\displaystyle \sf{ \implies }p(1) = 5 - 7 + 8 + 100$

$\displaystyle \sf{ \implies }p(1) = 106$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If p(x) = 2x + 1, then find p( -1)

https://brainly.in/question/20224817

2. if polynomial p(t)=t⁴-t³+t²+6,then find p(-1)

https://brainly.in/question/3539645

#SPJ2

Answer 2

$p(0)=100$ $and\ p(1)=106$

Given:

$p(x)=5x^{3} -7x^{2} +8x+100$

Solution:

To find p(0) put x=0 in the above polynomial.

$p(0)=5\times 0^{3} -7\times 0^{2} +8\times 0+100\\p(0)=0-0+0+100\\\therefore p(0)=100$

To find p(1) put x=1 in the above polynomial.

$p(1)=5\times 1^{3} -7\times 1^{2} +8\times 1+100\\p(1)=5\times 1-7\times 1+8+100\\p(1)=5-7+8+100\\\therefore p(1)=106$

For more such questions, click on the below links.

If 2 is a zero of the polynomial p(x) =5x³-2x²+3x-a. find a​

https://brainly.in/question/20133923

What is the coefficient of the polynomial p(x)=5x³-6x-x7+5

https://brainly.in/question/50195752

#SPJ2