p(x,6) is the midpoint of seg AB with A(6,5) and B(4,y) then y=?
Answers
Answered by
11
Answer:
y = 7
Step-by-step explanation:
Given,
p(x, 6) is mid point A(6, 5) and B(4, y).
Using mid point formula,
(x, y) = [(x1 + x2)/2 , (y1 + y2)/2]
(x, 6) = [(6 + 4)/2 , (5 + y)/2]
(x, 6) = [10/2, (5 + y)/2]
(x, 6) = (5, (5+y)/2)
Comparing corresponding coordinates,
6 = (5 + y)/2
12 = 5 + y
12 - 5 = y
7 = y
So required value of y is 7.
Answered by
3
Step-by-step explanation:
P(x,6) is (x,y), A(6,5) is (X1,Y1), B(4,y) is (X2,Y2)
By midpoint formula
X=X1+X2÷2 & Y=Y1+Y2÷2
put value
X=6+4÷2 & 6=5+Y÷2
X=10÷2 & 6×2=5+Y
X =5. & 12=5+Y =12-5=Y =7
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