Question

P(x)=6x³-11x²+kx-20
X=4by3

Answer 1

On putting the value of root of a polynomial into that polynomial we get 0

so, 6(4/3)^3-11(4/3)^2+k4/3-20=0

→128/9-176/9+k4/3 -20=0

→-48/9+k4/3 -20=0

→-16/3+k4/3 -20=0

→(4k-16)/3=20

→4k-16=60

→4k=76

→k=19

Answer 2

On putting the value of root of a polynomial into that polynomial we get 0

so, 6(4/3)^3-11(4/3)^2+k4/3-20=0

→128/9-176/9+k4/3 -20=0

→-48/9+k4/3 -20=0

→-16/3+k4/3 -20=0

→(4k-16)/3=20

→4k-16=60

→4k=76

→k=19