p(x)= 7x square - 4 root 2x - 6 ,g(x) = x- root 2, show that p(x) is the factor of g(x)
...can you please write this answer it's better to just click photos..
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If g(x) is a factor of p(x), then g(x) = 0 and p(x) = 0
So, x- root2 = 0
=> x = root2
Now, p(root2) = 7(root2)^2 - 4(root2)(root2)-6 = 0
Hence, g(x) is a factor of p(x).
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